evidencia 4

Obtenga la Distribución de Bernoulli si se tiran a lo más 8 lanzamientos de una moneda.F (*) = nCx Px Qn-x

Datos:

N: 8P: ½=50%=0.5Q: 0.5X:
a lo más va de 0 al 8

F (0) = 8C0 (0.5)0 (0.5)8-0 = (1) (1) (3.90625*10)-3 = 3.90625*10-3
F (1) = 8C1 (0.5)1 (0.5)8-1 = (8) (0.5) (7.8125*10)-3 = 0.03125
F (2) = 8C2 (0.5)2 (0.5)8-2 = (28) (0.25) (0.015625) = 0.109375
F (3) = 8C3 (0.5)3 (0.5)8-3 = (56) (0.125) (0.03125) = 0.21875
F (4) = 8C4 (0.5)4 (0.5)8-4 = (70) (0.625) (0.0625) = 0.2734375
F (5) = 8C5 (0.5)5 (0.5)8-5 = (56) (0.03125) (0.125) = 0.21875
F (6) = 8C6 (0.5)6 (0.5)8-6 = (28) (0.015625) (0.25) = 0.109375
F (7) = 8C7 (0.5)7 (0.5)8-7 = (8) (7.8125*10)-3 (0.5) = 0.03125
F (8) = 8C8 (0.5)8 (0.5)8-8 = (1) (3.90625*10)-3 (1) = 3.9625*10-3